(-y+3)/(3y^2)=0

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Solution for (-y+3)/(3y^2)=0 equation: 



(-y+3)/(3y^2)=0



Domain of the equation: 3y^2!=0

y^2!=0/3

y^2!=√0

y!=0

y∈R



We add all the numbers together, and all the variables

(-1y+3)/3y^2=0

We multiply all the terms by the denominator


(-1y+3)=0

We get rid of parentheses

-1y+3=0

We move all terms containing y to the left, all other terms to the right

-y=-3

y=-3/-1

y=+3

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